Aleksandrów (Kłobuck Kūn)

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Aleksandrów
—  Chng-thâu  —
Aleksandrów is located in Pho-lân
Aleksandrów
Aleksandrów
Keng-hūi-tō͘: 50°55′N 18°43′E / 50.917°N 18.717°E / 50.917; 18.717
Kok-ka  Pho-lân
Séng Silesia
Kūn Kłobuck
Kong-siā Panki
Sî-khu CET (UTC+1)
 - Jo̍at--lâng CEST (UTC+2)

Aleksandrów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Silesia Séng Kłobuck Kūn Panki Kong-siā ê chng-thâu.[1]

Chham-oa̍t[siu-kái | kái goân-sí-bé]

Chham-khó[siu-kái | kái goân-sí-bé]

  1. ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01. 
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