Alfred (New York)

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Alfred
—  Chng-thâu (town)  —
Alfred ê kéng-sek
Alfred ê kéng-sek
Alfred is located in New York
Alfred
Alfred
Alfred tī Bí-kok New York ê ūi-tì
Keng-hūi-tō͘: 42°15′20″N 77°47′20″W / 42.25556°N 77.78889°W / 42.25556; -77.78889
Kok-ka  Bí-kok
Chiu New York
Kūn Allegany
Chèng-hú
 - Lūi-hêng ''town''
Bīn-chek
 - Lóng-chóng 3.1 km2
Koân-tō͘ 501 m
Jîn-kháu
 - Lóng-chóng 5,140 lâng
 - Bi̍t-tō͘ 1,658.1/km2

AlfredBí-kok New York chiu Allegany kūn ê chi̍t ê chng-thâu (town).

Jîn-kháu[siu-kái | kái goân-sí-bé]

Chit ūi tī 2010 nî ê jîn-kháu-sò͘ sī 5,237 lâng.


Che sī chi̍t phiⁿ koan-î Bí-kok New York Chiu tē-lí ê phí-á-kiáⁿ. Chhiáⁿ tàu khok-chhiong.