Port Jefferson (Ohio)
Port Jefferson | |
— Chng-thâu (village) — | |
Port Jefferson tī Bí-kok Ohio ê ūi-tì | |
Keng-hūi-tō͘: 40°19′49″N 84°5′27″W / 40.33028°N 84.09083°W | |
Kok-ka | Bí-kok |
---|---|
Chiu | Ohio |
Kūn | Shelby |
Chèng-hú | |
- Lūi-hêng | village |
Bīn-chek | |
- Lóng-chóng | 0.4 km2 |
Koân-tō͘ | 318 m |
Jîn-kháu | |
- Lóng-chóng | 324 lâng |
- Bi̍t-tō͘ | 810/km2 |
Port Jefferson sī Bí-kok Ohio chiu Shelby kūn ê chi̍t ê chng-thâu (village).
Jîn-kháu[siu-kái | kái goân-sí-bé]
Chit ūi tī 2010 nî ê jîn-kháu-sò͘ sī 371 lâng.