Warrensville Heights (Ohio)

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Warrensville Heights
—  Chng-thâu (city)  —
Warrensville Heights só͘-chāi-tô͘ ê uī-tì
Warrensville Heights só͘-chāi-tô͘
Warrensville Heights is located in Ohio
Warrensville Heights
Warrensville Heights
Warrensville Heights tī Bí-kok Ohio ê ūi-tì
Keng-hūi-tō͘: 41°26′19″N 81°31′23″W / 41.43861°N 81.52306°W / 41.43861; -81.52306
Kok-ka Flag of the United States.svg Bí-kok
Chiu Ohio
Kūn Cuyahoga
Chèng-hú
 - Lūi-hêng city
Bīn-chek
 - Lóng-chóng 10.7 km2
Jîn-kháu
 - Lóng-chóng 13,967 lâng
 - Bi̍t-tō͘ 1,305.3/km2

Warrensville HeightsBí-kok Ohio chiu Cuyahoga kūn ê chi̍t ê chng-thâu (city).

Tē-lí[siu-kái | kái goân-sú-bé]

Tī pún só͘-chāi sì-ûi ê tē-hng ū Highland Hills, Cleveland, Maple Heights, Beachwood, Bedford Heights, North Randall, Orange, kap Shaker Heights.

Liân-kiat[siu-kái | kái goân-sú-bé]


Flag of Ohio.svg Che sī chi̍t phiⁿ koan-î Bí-kok Ohio Chiu tē-lí ê phí-á-kiáⁿ. Chhiáⁿ tàu khok-chhiong.