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Aleksandrów (Kalisz Kūn)

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Aleksandrów
—  Chng-thâu  —
Aleksandrów is located in Pho-lân
Aleksandrów
Aleksandrów
Keng-hūi-tō͘: 51°54′N 18°13′E / 51.900°N 18.217°E / 51.900; 18.217
Kok-ka  Pho-lân
Séng Tōa Pho-lân
Kūn Kalisz
Kong-siā Mycielin
Sî-khu CET (UTC+1)
 - Jo̍at--lâng CEST (UTC+2)

Aleksandrów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Tōa Pho-lân Séng Kalisz Kūn Mycielin Kong-siā ê chng-thâu.[1]

Chham-oa̍t

[siu-kái | kái goân-sí-bé]

Chham-khó

[siu-kái | kái goân-sí-bé]
  1. ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01. 
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