Aleksandrów (Opole Séng)
| Aleksandrów | |
| — Chng-thâu — | |
  Aleksandrów |
|
| Keng-hūi-tō͘: 51°6′N 18°29′E / 51.100°N 18.483°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Opole |
| Kūn | Olesno |
| Kong-siā | Praszka |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Aleksandrów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Opole Séng Olesno Kūn Praszka Kong-siā ê chng-thâu.[1]
Chham-oa̍t
[siu-kái | kái goân-sí-bé]Chham-khó
[siu-kái | kái goân-sí-bé]- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.