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Aleksandrówka (Lubartów Kūn)

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Aleksandrówka
—  Chng-thâu  —
Aleksandrówka is located in Pho-lân
Aleksandrówka
Aleksandrówka
Keng-hūi-tō͘: 51°29′N 22°24′E / 51.483°N 22.400°E / 51.483; 22.400
Kok-ka  Pho-lân
Séng Lublin Séng
Kūn Lubartów Kūn
Kong-siā Michów Kong-siā
Sî-khu CET (UTC+1)
 - Jo̍at--lâng CEST (UTC+2)

Aleksandrówka sī chi̍t ê tī Pho-lân Kiōng-hô-kok Lublin Séng Lubartów Kūn Michów Kong-siā ê chng-thâu.[1]

Chham-oa̍t

[siu-kái | kái goân-sí-bé]

Chham-khó

[siu-kái | kái goân-sí-bé]
  1. ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01. 
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