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Sokołów (Pruszków Kūn)

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Sokołów
—  Chng-thâu  —
Sokołów is located in Pho-lân
Sokołów
Sokołów
Keng-hūi-tō͘: 52°8′N 20°52′E / 52.133°N 20.867°E / 52.133; 20.867
Kok-ka  Pho-lân
Séng Masovia
Kūn Pruszków
Kong-siā Michałowice
Sî-khu CET (UTC+1)
 - Jo̍at--lâng CEST (UTC+2)

Sokołów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Masovia Séng Pruszków Kūn Michałowice Kong-siā ê chng-thâu.[1]

Chham-oa̍t

[siu-kái | kái goân-sí-bé]

Chham-khó

[siu-kái | kái goân-sí-bé]
  1. ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01. 
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