Sokołowo (Gniezno Kūn)
Guā-māu
Sokołowo | |
— Chng-thâu — | |
Keng-hūi-tō͘: 52°29′N 17°50′E / 52.483°N 17.833°E | |
Kok-ka | Pho-lân |
---|---|
Séng | Tōa Pho-lân |
Kūn | Gniezno |
Kong-siā | Witkowo |
Sî-khu | CET (UTC+1) |
- Joa̍h-tang | CEST (UTC+2) |
Sokołowo sī chi̍t ê tī Pho-lân Kiōng-hô-kok Tōa Pho-lân Séng Gniezno Kūn Witkowo Kong-siā ê chng-thâu.[1]
Chham-oa̍t
[siu-kái | kái goân-sí-bé]Chham-khó
[siu-kái | kái goân-sí-bé]- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.