Jankowice (Chrzanów Kūn)
| Jankowice | |
| — Chng-thâu — | |
  Jankowice |
|
| Keng-hūi-tō͘: 50°2′35″N 19°26′26″E / 50.04306°N 19.44056°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Sió Pho-lân Séng |
| Kūn | Chrzanów Kūn |
| Kong-siā | Babice Kong-siā |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Jankowice sī chi̍t ê tī Pho-lân Kiōng-hô-kok Sió Pho-lân Séng Chrzanów Kūn Babice Kong-siā ê chng-thâu.[1]
Chham-oa̍t
[siu-kái | kái goân-sí-bé]Chham-khó
[siu-kái | kái goân-sí-bé]- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.