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Popielów (Opole Séng)

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Popielów
—  Chng-thâu  —
Popielów is located in Pho-lân
Popielów
Popielów
Keng-hūi-tō͘: 50°49′33″N 17°44′31″E / 50.82583°N 17.74194°E / 50.82583; 17.74194
Kok-ka  Pho-lân
Séng Opole
Kūn Opole
Kong-siā Popielów
Sî-khu CET (UTC+1)
 - Jo̍at--lâng CEST (UTC+2)

Popielów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Opole Séng Opole Kūn Popielów Kong-siā ê chng-thâu.[1]

Chham-oa̍t[siu-kái | kái goân-sí-bé]

Chham-khó[siu-kái | kái goân-sí-bé]