Schuilenburg (Friesland)
| Schuilenburg | |||
| — Chng-thâu — | |||
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  Schuilenburg |
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| Keng-hūi-tō͘: 53°12′0″N 6°4′0″E / 53.20000°N 6.06667°E | |||
| Kok-ka |  Hô-lân
| ||
|---|---|---|---|
| Séng | Friesland | ||
| Chū-tī-thé | Tietjerksteradeel | ||
Schuilenburg sī Hô-lân Friesland séng Tietjerksteradeel chū-tī-thé lāi-bīn ê chi̍t ê chng-thâu.