Seymour (Indiana)

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Seymour
—  Chng-thâu (city)  —
Seymour is located in Indiana
Seymour
Seymour
Seymour tī Bí-kok Indiana ê ūi-tì
Keng-hūi-tō͘: 38°57′22″N 85°53′24″W / 38.95611°N 85.89000°W / 38.95611; -85.89000
Kok-ka Flag of the United States.svg Bí-kok
Chiu Indiana
Kūn Jackson
Chèng-hú
 - Lūi-hêng city
Bīn-chek
 - Lóng-chóng 28.1 km2
Koân-tō͘ 171 m
Jîn-kháu
 - Lóng-chóng 19,111 lâng
 - Bi̍t-tō͘ 680.1/km2

SeymourBí-kok Indiana chiu Jackson kūn ê chi̍t ê chng-thâu (city).

Jîn-kháu[siu-kái | kái goân-sú-bé]

Chit ūi tī 2010 nî ê jîn-kháu-sò͘ sī 17,503 lâng.

Liân-kiat[siu-kái | kái goân-sú-bé]


Flag map of Indiana.svg Che sī chi̍t phiⁿ koan-î Bí-kok Indiana Chiu tē-lí ê phí-á-kiáⁿ. Chhiáⁿ tàu khok-chhiong.