Sukhaya (Alexandrovsky Koān, Perm Pian-kiong-khu)
| Sukhaya Сухая |
|
| — Chū-lo̍h — | |
  Sukhaya  Sukhaya |
|
| Keng-hūi-tō͘: 59°33′N 57°48′E / 59.550°N 57.800°E | |
| Kok-ka |  Lō͘-se-a
|
|---|---|
| Liân-pang chú-thé | Perm |
| Koān | Alexandrovsky |
| Jîn-kháu | |
| - Lóng-chóng | 31 lâng |
Sukhaya (Lō͘-se-a-gí: Сухая) sī chi̍t ê tī Lō͘-se-a Liân-pang Perm Pian-kiong-khu Alexandrovsky Koān ê chng-kha só͘-chāi (chū-lo̍h).[1] Tī 2010 nî phó͘-cha ê sî-chūn, chit-ê só͘-chāi ū 31 ê lâng tòa.[2] Hia ū 7 tiâu ke-á-lō͘.